## README ¶

### 798. Smallest Rotation with Highest Score

#### 题目

Given an array A, we may rotate it by a non-negative integer K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1]. Afterward, any entries that are less than or equal to their index are worth 1 point.

For example, if we have [2, 4, 1, 3, 0], and we rotate by K = 2, it becomes [1, 3, 0, 2, 4]. This is worth 3 points because 1 > 0 [no points], 3 > 1 [no points], 0 <= 2 [one point], 2 <= 3 [one point], 4 <= 4 [one point].

Over all possible rotations, return the rotation index K that corresponds to the highest score we could receive. If there are multiple answers, return the smallest such index K.

```
Example 1:
Input: [2, 3, 1, 4, 0]
Output: 3
Explanation:
Scores for each K are listed below:
K = 0, A = [2,3,1,4,0], score 2
K = 1, A = [3,1,4,0,2], score 3
K = 2, A = [1,4,0,2,3], score 3
K = 3, A = [4,0,2,3,1], score 4
K = 4, A = [0,2,3,1,4], score 3
```

So we should choose K = 3, which has the highest score.

```
Example 2:
Input: [1, 3, 0, 2, 4]
Output: 0
Explanation: A will always have 3 points no matter how it shifts.
So we will choose the smallest K, which is 0.
```

Note:

- Awill havelength at most 20000.
- A[i] will be in the range [0, A.length].

#### 解题思路

见程序注释

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