Additive number is a string whose digits can form additive sequence.
A valid additive sequence should contain at least three numbers. Except for the first two numbers, each subsequent number in the sequence must be the sum of the preceding two.
Given a string containing only digits '0'-'9'
, write a function to determine if it's an additive number.
Note: Numbers in the additive sequence cannot have leading zeros, so sequence 1, 2, 03
or 1, 02, 3
is invalid.
Example 1:
**Input:** "112358"
**Output:** true
**Explanation:** The digits can form an additive sequence: 1, 1, 2, 3, 5, 8.
1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8
Example 2:
**Input:** "199100199"
**Output:** true
**Explanation:** The additive sequence is: 1, 99, 100, 199.
1 + 99 = 100, 99 + 100 = 199
Follow up:
How would you handle overflow for very large input integers?
思路
从头开始选第一个数、第二个数和剩下的数,判断剩下的数开头是不是第一个数和第二个数的和,如果是则第一个数换成第二个数,第二个数换成和,剩下的数排除为和的数,再判断剩下的数,直到没有剩下的数,返回 true
,否则第二个数加一位,然后继续判断,如果第二个数取到了最后一位还没有返回 true
,那么第一个数加一位,继续下去。
如果第一个数是 0
开头并且不等于 0
那么可以直接返回 false
。
如果第二个数是 0
开头并且不等于 0
那么直接递增第一个数。