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Given two strings s1
and s2
, return true
if s2
contains a permutation of s1
, or false
otherwise.
In other words, return true
if one of s1
's permutations is the substring of s2
.
Example 1:
Input: s1 = "ab", s2 = "eidbaooo"
Output: true
Explanation: s2 contains one permutation of s1 ("ba").
Example 2:
Input: s1 = "ab", s2 = "eidboaoo"
Output: false
Constraints:
1 <= s1.length, s2.length <= 104
s1
and s2
consist of lowercase English letters.
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Similar Questions
- Minimum Window Substring (Hard)
- Find All Anagrams in a String (Medium)
Hints
Hint 1
Obviously, brute force will result in TLE. Think of something else.
Hint 2
How will you check whether one string is a permutation of another string?
Hint 3
One way is to sort the string and then compare. But, Is there a better way?
Hint 4
If one string is a permutation of another string then they must one common metric. What is that?
Hint 5
Both strings must have same character frequencies, if one is permutation of another. Which data structure should be used to store frequencies?
Hint 6
What about hash table? An array of size 26?