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Given a positive integer k
, you need to find the length of the smallest positive integer n
such that n
is divisible by k
, and n
only contains the digit 1
.
Return the length of n
. If there is no such n
, return -1.
Note: n
may not fit in a 64-bit signed integer.
Example 1:
Input: k = 1
Output: 1
Explanation: The smallest answer is n = 1, which has length 1.
Example 2:
Input: k = 2
Output: -1
Explanation: There is no such positive integer n divisible by 2.
Example 3:
Input: k = 3
Output: 3
Explanation: The smallest answer is n = 111, which has length 3.
Constraints:
[Hash Table]
[Math]
Hints
Hint 1
11111 = 1111 * 10 + 1
We only need to store remainders modulo K.
Hint 2
If we never get a remainder of 0, why would that happen, and how would we know that?