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Published: Jul 18, 2021 License: MIT Imports: 0 Imported by: 0

README

981. Time Based Key-Value Store

[中等] 哈希表 二分查找


创建一个基于时间的键值存储类 TimeMap,它支持下面两个操作:

1. set(string key, string value, int timestamp)


	存储键 key、值 value,以及给定的时间戳 timestamp。


2. get(string key, int timestamp)


	返回先前调用 set(key, value, timestamp_prev) 所存储的值,其中 timestamp_prev <= timestamp。
	如果有多个这样的值,则返回对应最大的  timestamp_prev 的那个值。
	如果没有值,则返回空字符串("")。


 

示例 1:

输入:inputs = ["TimeMap","set","get","get","set","get","get"], inputs = [[],["foo","bar",1],["foo",1],["foo",3],["foo","bar2",4],["foo",4],["foo",5]]
输出:[null,null,"bar","bar",null,"bar2","bar2"]
解释:  
TimeMap kv;   
kv.set("foo", "bar", 1); // 存储键 "foo" 和值 "bar" 以及时间戳 timestamp = 1   
kv.get("foo", 1);  // 输出 "bar"   
kv.get("foo", 3); // 输出 "bar" 因为在时间戳 3 和时间戳 2 处没有对应 "foo" 的值,所以唯一的值位于时间戳 1 处(即 "bar")   
kv.set("foo", "bar2", 4);   
kv.get("foo", 4); // 输出 "bar2"   
kv.get("foo", 5); // 输出 "bar2"   



示例 2:

输入:inputs = ["TimeMap","set","set","get","get","get","get","get"], inputs = [[],["love","high",10],["love","low",20],["love",5],["love",10],["love",15],["love",20],["love",25]]
输出:[null,null,null,"","high","high","low","low"]


 

提示:


	所有的键/值字符串都是小写的。
	所有的键/值字符串长度都在 [1, 100] 范围内。
	所有 TimeMap.set 操作中的时间戳 timestamps 都是严格递增的。
	1 <= timestamp <= 10^7
	TimeMap.set 和 TimeMap.get 函数在每个测试用例中将(组合)调用总计 120000 次。


Documentation

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Types

type TimeMap

type TimeMap struct {
	Val  map[string][]string
	Time map[string][]int
}

func Constructor

func Constructor() TimeMap

func (*TimeMap) Get

func (tm *TimeMap) Get(key string, timestamp int) string

func (*TimeMap) Set

func (tm *TimeMap) Set(key string, value string, timestamp int)

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