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165. Compare Version Numbers (Medium)
Compare two version numbers version1 and version2.
If version1 > version2
return 1;
if version1 < version2
return -1;
otherwise return 0
.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
You may assume the default revision number for each level of a version number to be 0
. For example, version number 3.4
has a revision number of 3
and 4
for its first and second level revision number. Its third and fourth level revision number are both 0
.
Example 1:
Input: version1
= "0.1", version2
= "1.1"
Output: -1
Example 2:
Input: version1
= "1.0.1", version2
= "1"
Output: 1
Example 3:
Input: version1
= "7.5.2.4", version2
= "7.5.3"
Output: -1
Example 4:
Input: version1
= "1.01", version2
= "1.001"
Output: 0
Explanation: Ignoring leading zeroes, both “01” and “001" represent the same number “1”
Example 5:
Input: version1
= "1.0", version2
= "1.0.0"
Output: 0
Explanation: The first version number does not have a third level revision number, which means its third level revision number is default to "0"
Note:
- Version strings are composed of numeric strings separated by dots
.
and this numeric strings may have leading zeroes.
- Version strings do not start or end with dots, and they will not be two consecutive dots.
[String]