Given a matrix consisting of 0s and 1s, we may choose any number of columns in the matrix and flip every cell in that column. Flipping a cell changes the value of that cell from 0 to 1 or from 1 to 0.
Return the maximum number of rows that have all values equal after some number of flips.
Example 1:
Input: [[0,1],[1,1]]Output: 1Explanation: After flipping no values, 1 row has all values equal.
Example 2:
Input: [[0,1],[1,0]]Output: 2Explanation: After flipping values in the first column, both rows have equal values.
Example 3:
Input: [[0,0,0],[0,0,1],[1,1,0]]Output: 2Explanation: After flipping values in the first two columns, the last two rows have equal values.
Hint 1
Flipping a subset of columns is like doing a bitwise XOR of some number K onto each row. We want rows X with X ^ K = all 0s or all 1s. This is the same as X = X^K ^K = (all 0s or all 1s) ^ K, so we want to count rows that have opposite bits set. For example, if K = 1, then we count rows X = (00000...001, or 1111....110).