problem1032

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1032. Stream of Characters (Hard)

Implement the StreamChecker class as follows:

• StreamChecker(words): Constructor, init the data structure with the given words.
• query(letter): returns true if and only if for some k >= 1, the last k characters queried (in order from oldest to newest, including this letter just queried) spell one of the words in the given list.

 

Example:

StreamChecker streamChecker = new StreamChecker(["cd","f","kl"]); // init the dictionary.
streamChecker.query('a');          // return false
streamChecker.query('b');          // return false
streamChecker.query('c');          // return false
streamChecker.query('d');          // return true, because 'cd' is in the wordlist
streamChecker.query('e');          // return false
streamChecker.query('f');          // return true, because 'f' is in the wordlist
streamChecker.query('g');          // return false
streamChecker.query('h');          // return false
streamChecker.query('i');          // return false
streamChecker.query('j');          // return false
streamChecker.query('k');          // return false
streamChecker.query('l');          // return true, because 'kl' is in the wordlist

 

Note:

• 1 <= words.length <= 2000
• 1 <= words[i].length <= 2000
• Words will only consist of lowercase English letters.
• Queries will only consist of lowercase English letters.
• The number of queries is at most 40000.

Related Topics

[Trie]

Hints

Hint 1

Put the words into a trie, and manage a set of pointers within that trie.

Documentation

Index

• type StreamChecker
  • func Constructor(words []string) StreamChecker
  • func (sc *StreamChecker) Query(letter byte) bool

Types

type StreamChecker

type StreamChecker struct {
	// contains filtered or unexported fields
}

StreamChecker check letters

func Constructor

func Constructor(words []string) StreamChecker

Constructor returns StreamChecker

func (*StreamChecker) Query

func (sc *StreamChecker) Query(letter byte) bool

Query returns true if letter in words