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Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
Implement the MinStack
class:
MinStack()
initializes the stack object.
void push(val)
pushes the element val
onto the stack.
void pop()
removes the element on the top of the stack.
int top()
gets the top element of the stack.
int getMin()
retrieves the minimum element in the stack.
Example 1:
Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
Output
[null,null,null,null,-3,null,0,-2]
Explanation
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top(); // return 0
minStack.getMin(); // return -2
Constraints:
-231 <= val <= 231 - 1
- Methods
pop
, top
and getMin
operations will always be called on non-empty stacks.
- At most
3 * 104
calls will be made to push
, pop
, top
, and getMin
.
[Stack]
[Design]
Similar Questions
- Sliding Window Maximum (Hard)
- Max Stack (Easy)
Hints
Hint 1
Consider each node in the stack having a minimum value. (Credits to @aakarshmadhavan)