Given
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A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers.
Given a string s
, return true
if it is a palindrome, or false
otherwise.
Example 1:
Input: s = "A man, a plan, a canal: Panama"
Output: true
Explanation: "amanaplanacanalpanama" is a palindrome.
Example 2:
Input: s = "race a car"
Output: false
Explanation: "raceacar" is not a palindrome.
Example 3:
Input: s = " "
Output: true
Explanation: s is an empty string "" after removing non-alphanumeric characters.
Since an empty string reads the same forward and backward, it is a palindrome.
Constraints:
1 <= s.length <= 2 * 10^5
s
consists only of printable ASCII characters.
Solution
Golang solution
import (
"regexp"
"strings"
)
func reverse(s string) string {
r := []rune(s)
for i, j := 0, len(r)-1; i < len(r)/2; i, j = i+1, j-1 {
r[i], r[j] = r[j], r[i]
}
return string(r)
}
func isPalindrome(s string) bool {
s = strings.ToLower(s)
re, _ := regexp.Compile(`[^a-zA-Z0-9]+`)
new_text := re.ReplaceAllString(s, "")
return new_text == reverse(new_text)
}
Python solution
class Solution:
def isPalindrome(self, s: str) -> bool:
s = s.lower()
# remove all non alphanumeric characters using isalnum()
s = [c for c in s if c.isalnum()]
return s == s[::-1]