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Implement a last in first out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal queue (push
, top
, pop
, and empty
).
Implement the MyStack
class:
void push(int x)
Pushes element x to the top of the stack.
int pop()
Removes the element on the top of the stack and returns it.
int top()
Returns the element on the top of the stack.
boolean empty()
Returns true
if the stack is empty, false
otherwise.
Notes:
- You must use only standard operations of a queue, which means only
push to back
, peek/pop from front
, size
, and is empty
operations are valid.
- Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue), as long as you use only a queue's standard operations.
Example 1:
Input
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 2, 2, false]
Explanation
MyStack myStack = new MyStack();
myStack.push(1);
myStack.push(2);
myStack.top(); // return 2
myStack.pop(); // return 2
myStack.empty(); // return False
Constraints:
1 <= x <= 9
- At most
100
calls will be made to push
, pop
, top
, and empty
.
- All the calls to
pop
and top
are valid.
Follow-up: Can you implement the stack such that each operation is amortized O(1)
time complexity? In other words, performing n
operations will take overall O(n)
time even if one of those operations may take longer. You can use more than two queues.
[Stack]
[Design]
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