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Given a rooted binary tree, return the lowest common ancestor of its deepest leaves.
Recall that:
- The node of a binary tree is a leaf if and only if it has no children
- The depth of the root of the tree is 0, and if the depth of a node is
d
, the depth of each of its children is d+1
.
- The lowest common ancestor of a set
S
of nodes is the node A
with the largest depth such that every node in S is in the subtree with root A
.
Example 1:
Input: root = [1,2,3]
Output: [1,2,3]
Explanation:
The deepest leaves are the nodes with values 2 and 3.
The lowest common ancestor of these leaves is the node with value 1.
The answer returned is a TreeNode object (not an array) with serialization "[1,2,3]".
Example 2:
Input: root = [1,2,3,4]
Output: [4]
Example 3:
Input: root = [1,2,3,4,5]
Output: [2,4,5]
Constraints:
- The given tree will have between 1 and 1000 nodes.
- Each node of the tree will have a distinct value between 1 and 1000.
[Tree]
[Depth-first Search]
Hints
Hint 1
Do a postorder traversal.
Hint 2
Then, if both subtrees contain a deepest leaf, you can mark this node as the answer (so far).
Hint 3
The final node marked will be the correct answer.